mindspore.numpy.searchsorted
- mindspore.numpy.searchsorted(a, v, side='left', sorter=None)[源代码]
Finds indices where elements should be inserted to maintain order. Finds the indices into a sorted array a such that, if the corresponding elements in v were inserted before the indices, the order of a would be preserved.
- 参数
a (Union[list, tuple, Tensor]) – 1-D input array. If sorter is None, then it must be sorted in ascending order, otherwise sorter must be an array of indices that sort it.
v (Union[int, float, bool, list, tuple, Tensor]) – Values to insert into a.
side ('left', 'right', optional) – If ‘left’, the index of the first suitable location found is given. If ‘right’, return the last such index. If there is no suitable index, return either 0 or N (where N is the length of a).
sorter (Union[int, float, bool, list, tuple, Tensor]) – 1-D optional array of integer indices that sort array a into ascending order. They are typically the result of argsort.
- 返回
Tensor, array of insertion points with the same shape as v.
- 异常
ValueError – If argument for side or sorter is invalid.
- Supported Platforms:
Ascend
GPU
CPU
样例
>>> from mindspore import numpy as np >>> print(np.searchsorted([1,2,3,4,5], 3)) 2 >>> print(np.searchsorted([1,2,3,4,5], 3, side='right')) 3 >>> print(np.searchsorted([1,2,3,4,5], [-10, 10, 2, 3])) [0 5 1 2]