mindspore.Tensor.max
- Tensor.max(axis=None, keepdims=False, *, initial=None, where=True, return_indices=False)[source]
Return the maximum of a tensor or maximum along an axis.
Note
When axis is
None
, keepdims and subsequent parameters have no effect. At the same time, the index is fixed to return 0.- Parameters
axis (Union[None, int, list, tuple of ints], optional) – Axis or axes along which to operate. By default, flattened input is used. If this is a tuple of ints, the maximum is selected over multiple axes, instead of a single axis or all the axes as before. Default: None.
keepdims (bool, optional) – If this is set to True, the axes which are reduced are left in the result as dimensions with size one. With this option, the result will broadcast correctly against the input array. Default: False.
- Keyword Arguments
initial (scalar, optional) – The minimum value of an output element. Must be present to allow computation on empty slice. Default: None.
where (Tensor[bool], optional) – A boolean tensor which is broadcasted to match the dimensions of array, and selects elements to include in the reduction. If non-default value is passed, initial must also be provided. Default: True.
return_indices (bool, optional) – Whether to return the index of the maximum value. Default: False. If axis is a list or tuple of ints, it must be False.
- Returns
Tensor or scalar, maximum of input tensor. If axis is None, the result is a scalar value. If axis is given, the result is a tensor of dimension
self.ndim - 1
.- Raises
TypeError – If arguments have types not specified above.
- Supported Platforms:
Ascend
GPU
CPU
See also
mindspore.Tensor.argmin()
: Return the indices of the minimum values along an axis.mindspore.Tensor.argmax()
: Return the indices of the maximum values along an axis.mindspore.Tensor.min()
: Return the minimum of a tensor or minimum along an axis.Examples
>>> import numpy as np >>> from mindspore import Tensor >>> a = Tensor(np.arange(4).reshape((2, 2)).astype('float32')) >>> output = a.max() >>> print(output) 3.0 >>> value, indices = a.max(axis=0, return_indices=True) >>> print(value) [2. 3.] >>> print(indices) [1 1]