mindspore.train.Precision

class mindspore.train.Precision(eval_type='classification')

Calculates precision for classification and multilabel data.

The precision function creates two local variables, \(\text{true_positive}\) and \(\text{false_positive}\), which are used to compute the precision. The calculation formula is:

\[\text{precision} = \frac{\text{true_positive}}{\text{true_positive} + \text{false_positive}}\]

Parameters

eval_type (str) – 'classification' or 'multilabel' are supported. See the update method below for what it does. Default: 'classification' .

Supported Platforms:

Ascend GPU CPU

Examples

>>> import numpy as np
>>> from mindspore import Tensor
>>> from mindspore.train import Precision
>>>
>>> x = Tensor(np.array([[0.2, 0.5], [0.3, 0.1], [0.9, 0.6]]))
>>> y = Tensor(np.array([1, 0, 1]))
>>> metric = Precision('classification')
>>> metric.clear()
>>> metric.update(x, y)
>>> precision = metric.eval()
>>> print(precision)
[0.5 1. ]

clear()

Clears the internal evaluation result.

eval(average=False)

Computes the precision.

Parameters

average (bool) – Specify whether calculate the average precision. Default: False .

Returns

numpy.float64, the computed result.

update(*inputs)

Updates the internal evaluation result with y_pred and y. In the multi-label cases, the elements of

\(y\) and \(y_pred\) must be 0 or 1.

Parameters

inputs – Input y_pred and y. y_pred and y are Tensor, list or numpy.ndarray. For 'classification' evaluation type, y_pred is in most cases (not strictly) a list of floating numbers in range \([0, 1]\) and the shape is \((N, C)\), where \(N\) is the number of cases and \(C\) is the number of categories. Shape of y can be \((N, C)\) with values 0 and 1 if one-hot encoding is used or the shape is \((N,)\) with integer values if index of category is used. For 'multilabel' evaluation type, y_pred and y can only be one-hot encoding with values 0 or 1. Indices with 1 indicate positive category. The shape of y_pred and y are both \((N, C)\).

Raises

ValueError – If the number of inputs is not 2.