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Describe the bug so that we can quickly locate the problem.

mindspore.mint.cat

mindspore.mint.cat(tensors, dim=0)[source]

Connect input tensors along with the given dimension.

The input data is a tuple or a list of tensors. These tensors have the same rank R. Set the given dimension as m, and 0m<R. Set the number of input tensors as N. For the i-th tensor ti, it has the shape of (x1,x2,...,xmi,...,xR). xmi is the m-th dimension of the ti. Then, the shape of the output tensor is

(x1,x2,...,i=1Nxmi,...,xR)
Parameters
  • tensors (Union[tuple, list]) – A tuple or a list of input tensors. Suppose there are two tensors in this tuple or list, namely t1 and t2. To perform concat in the dimension 0 direction, except for the 0-th dimension, all other dimensions should be equal, that is, t1.shape[1]=t2.shape[1],t1.shape[2]=t2.shape[2],...,t1.shape[R1]=t2.shape[R1], where R represents the rank of tensor.

  • dim (int) – The specified dimension, whose value is in range [R,R). Default: 0 .

Returns

Tensor, the shape is (x1,x2,...,i=1Nxmi,...,xR). The data type is the same with tensors.

Raises
  • TypeError – If dim is not an int.

  • ValueError – If tensors have different dimension of tensor.

  • ValueError – If dim not in range [R,R).

  • ValueError – If tensor's shape in tensors except for dim are different.

  • ValueError – If tensors is an empty tuple or list.

Supported Platforms:

Ascend

Examples

>>> import mindspore
>>> import numpy as np
>>> from mindspore import Tensor
>>> from mindspore import mint
>>> input_x1 = Tensor(np.array([[0, 1], [2, 1]]).astype(np.float32))
>>> input_x2 = Tensor(np.array([[0, 1], [2, 1]]).astype(np.float32))
>>> output = mint.cat((input_x1, input_x2))
>>> print(output)
[[0. 1.]
 [2. 1.]
 [0. 1.]
 [2. 1.]]
>>> output = mint.cat((input_x1, input_x2), 1)
>>> print(output)
[[0. 1. 0. 1.]
 [2. 1. 2. 1.]]